Created
November 19, 2015 15:09
-
-
Save jm42/88b79a8bfaa2065a261b to your computer and use it in GitHub Desktop.
Bruteforce al problema de lamparitas
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| # Hay 1000 lamparitas numeradas del 1 al 1000, las que son numeros primos | |
| # tienen un interruptor que cambia el estado de la lamparita de el y de | |
| # todos sus multiplos. | |
| # Cual es el maximo de lamparitas que pueden haber prendidas? | |
| #def divisores(n): | |
| # d = [] | |
| # for i in range(1, n + 1): | |
| # if n % i == 0: | |
| # d.append(i) | |
| # return d | |
| #def es_primo(n): | |
| # return len(divisores(n)) == 2 | |
| #def primos_hasta(n): | |
| # p = [] | |
| # for i in range(1, n + 1): | |
| # if es_primo(i): | |
| # p.append(i) | |
| # return p | |
| #p = primos_hasta(1000) | |
| p = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, | |
| 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, | |
| 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199] | |
| # No van? | |
| t = [211, 223, | |
| 227, 229, 233, 239, 241] | |
| p = p + [251, 257, 263, 269, 271, 277, 281, 283, 293, | |
| 307, 311, 313, 317, 331] | |
| # Agregan y sacan uno | |
| #v = [337, 347, 349, 353, 359, 367, 373, 379, 383, | |
| # 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, | |
| # 467, 479, 487, 491, 499] | |
| c = [503, 509, 521, 523, 541, 547, 557, 563, 569, | |
| 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, | |
| 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, | |
| 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, | |
| 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, | |
| 947, 953, 967, 971, 977, 983, 991, 997] | |
| def combina(p, n): | |
| if n == 1: | |
| return [[d] for d in p] | |
| l = [] | |
| for d in combina(p, n - 1): | |
| for r in p: | |
| if r not in d: | |
| a = sorted(d + [r]) | |
| if not a in l: | |
| l.append(a) | |
| return l | |
| # 2 ** 168 = 374144419156711147060143317175368453031918731001856 | |
| # combina(p, 2) = 15865 | |
| def main(): | |
| s = None | |
| t = 0 | |
| for d in combina(p, 3): | |
| d = d + c | |
| l = [False for i in range(1001)] | |
| for i in d: | |
| for m in range(i, 1001, i): | |
| l[m] = not l[m] | |
| h = l.count(True) | |
| if h > t: | |
| s = d | |
| t = h | |
| print(s, t) | |
| main() |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment