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Read arbitrarily large input, print number closest to zero
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from itertools import islice, tee | |
# Assume an input such: | |
# | |
# 3 | |
# 1 -3 4 | |
# 2 | |
# 8 9 | |
# 0 | |
# | |
# 4 | |
# 1 3 8 2 | |
# | |
# Where the first line indicates the number of integers to be found | |
# on the next line: find the number on the next line that is nearest | |
# to zero (0) | |
with open("/dev/stdin") as file_: | |
# Split the `file_` into two iterators... | |
cnt_iter, num_iter = tee(file_) | |
# ... slice each to return every other row but start `num_iter` | |
# from index 1 ... | |
cnt_iter = islice(cnt_iter, 0, None, 2) | |
num_iter = islice(num_iter, 1, None, 2) | |
# ... iterate both iterators together ... | |
for nums, line in zip(cnt_iter, num_iter): | |
if int(nums) > 0: | |
# ... map each into an `int` and get the minimum as is | |
# reported by `abs()` -- this "ignores" negative value | |
# but still lets us retain their sign. | |
ints = map(int, line.split()) | |
low_ = min(ints, key=abs) | |
print(low_) |
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