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May 26, 2011 09:55
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Euler Project Problem #005
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# Solution to Project Euler's fifth problem | |
# http://projecteuler.net/index.php?section=problems&id=5 | |
# Find the smallest number divisible with no remainder by each number below twenty. | |
def generate_primes(ceiling) | |
primes, count = [1, 2], 1 | |
until primes.last > ceiling do | |
numbers = (primes[count-1]**2+1..primes[count]**2).to_a | |
1.upto(count) {|c| numbers.select! {|number| number%primes[c] != 0}} | |
primes.concat(numbers) | |
count += 1 | |
end | |
primes.shift #remove 1 | |
until primes.last < ceiling | |
primes.pop #remove last | |
end | |
return primes | |
end | |
def generate_exponents(factors) | |
ceiling = factors.last | |
until factors.first == ceiling do | |
if factors.first * factors.first < ceiling then | |
first = factors[0] | |
factors[0] = factors[0] * first | |
while factors[0] < ceiling/2 | |
factors[0] = factors[0] * first | |
end | |
end | |
factors.push factors.shift | |
puts factors.last | |
end | |
return factors | |
end | |
number, smallest = 20, 1 | |
factors = generate_primes(number) | |
factors = generate_exponents(factors) | |
p factors | |
factors.each do |f| | |
smallest = smallest * f | |
end | |
puts smallest |
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