Created
March 31, 2015 16:33
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TOI 2015 Test 2 Problem C
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#include <cstdio> | |
#include <cmath> | |
using namespace std; | |
double p[100001]; | |
double c[100000]; | |
int main() { | |
int maxn = 100000; | |
p[1] = 1; | |
c[0] = 1; | |
for(int n = 2, l = 0, r = 1; n <= maxn; n++, r++) { | |
// recompute c | |
for(int i = r; i > l; i--) | |
if((c[i] = (c[i] + c[i - 1]) / 2) < 1e-22) { | |
if(i == r) | |
r--; | |
else { | |
c[l = i] = 0; | |
break; | |
} | |
} | |
c[0] /= 2; | |
double pp = 0; | |
for(int i = l + 1; i < r; i++) | |
pp += c[i] * p[n - i]; | |
p[n] = (pp / 2 + pow(0.5, n - 1)) / (1 - pow(0.5, n)); | |
if(n == maxn) | |
fprintf(stderr, "(%d, %d)\n", l, r); | |
} | |
// CBD (x45) : 0.000014426949103667154302777821117675927098 | |
// no cut : 0.000014426949103667208512886445392897627471 using 8.921 s ( 0, 99999) | |
// cut at 0 : 0.000014426949103667208512886445392897627471 using 3.640 s (43942, 56056) | |
// cut 1e-100 : 0.000014426949103667208512886445392897627471 using 0.966 s (46676, 53327) | |
// cut 1e-22 : 0.000014426949103667208512886445392897627471 using 0.443 s (48575, 51435) | |
// cut 1e-10 : 0.000014426767339002582484137372775823138227 using 0.270 s (49214, 50806) | |
printf("%.42f\n", p[maxn]); | |
} |
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