A simple bash script that will open a `.xcworkspace` if it exists in the current directory, otherwise a `.xcodeproj` if it exists, otherwise nothing. It will print the name of the file that is being opened. When using Cocoapods with iOS apps, a second file is created with the `MyProject.xcworkspace` name, alongside the `MyProject.xcproject` file…

openx_bash_for_ios

# Add the following lines of code to your `~/.bash_profile`,
# and then run `source ~/.bash_profile` to be able to execute 
# this from the command line.

openx() {
    fileToOpen='';
    for file in `find . -maxdepth 1 -name *.xcworkspace`; do
        fileToOpen=$file
    done

    if [ -n "$fileToOpen" ]
    then
        echo $fileToOpen
        open $fileToOpen
    else
        for file in `find . -maxdepth 1 -name *.xcodeproj`; do
            fileToOpen=$file
        done

        if [ -n "$fileToOpen" ]
        then
            echo $fileToOpen
            open $fileToOpen
        else
            echo "No xcode files to open."
        fi
    fi
}

# Shorthand version of "openx", use "ox" instead.
ox() {
    openx
}

alias ox=openx

Nice idea but this doesn't support workspace or project files with spaces in the name unfortunately.

Thank you for this script !! 👍

Nice one.

you should probably change the for ... find with:

find . -maxdepth 1 -name *.xcworkspace -print0 | while IFS= read -r -d '' file; do
respectively
find . -maxdepth 1 -name *. xcodeproj -print0 | while IFS= read -r -d '' file; do

in case your project/workspace filename contains whitespaces.