Created
October 27, 2017 12:00
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Given a square matrix of at least 3x3, print its elements following a spiral path
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function print(o){ | |
var | |
m = o.length >> 1, | |
r = m, | |
c = m + 1; | |
p = function(){ | |
console.log(o[r][c]); | |
}, | |
left = function(i){ | |
for(; c > i; p(--c)); | |
}, | |
right = function(i){ | |
for(; c < i; p(++c)); | |
}, | |
up = function(i){ | |
for(; r > i; p(--r)); | |
}, | |
down = function(i){ | |
for(; r < i; p(++r)); | |
}; | |
for(var i = 0; ++i <= m; ){ | |
left(m - i); | |
down(m + i); | |
right(m + i); | |
up(m - i); | |
} | |
left(0); | |
} | |
print([ | |
[ 1, 2, 3, 4, 5], | |
[ 6, 7, 8, 9, 10], | |
[11, 12, 13, 14, 15], | |
[16, 17, 18, 19, 20], | |
[21, 22, 23, 24, 25] | |
]); |
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