Created
August 12, 2012 08:09
-
-
Save jonathanconway/3330614 to your computer and use it in GitHub Desktop.
Determine whether a type is simple.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
public static class TypeExtensions | |
{ | |
/// <summary> | |
/// Determine whether a type is simple (String, Decimal, DateTime, etc) | |
/// or complex (i.e. custom class with public properties and methods). | |
/// </summary> | |
/// <see cref="http://stackoverflow.com/questions/2442534/how-to-test-if-type-is-primitive"/> | |
public static bool IsSimpleType( | |
this Type type) | |
{ | |
return | |
type.IsValueType || | |
type.IsPrimitive || | |
new Type[] { | |
typeof(String), | |
typeof(Decimal), | |
typeof(DateTime), | |
typeof(DateTimeOffset), | |
typeof(TimeSpan), | |
typeof(Guid) | |
}.Contains(type) || | |
Convert.GetTypeCode(type) != TypeCode.Object; | |
} | |
} |
Thank!!!
IsValueType
returns true for Collections which I don't want. I just removed it from your condition and used it.
That seems to do the job for me:
public static bool IsPrimitiveType(Type type) { return (type == typeof(object) || Type.GetTypeCode(type) != TypeCode.Object); }
I found it on the same page on stackoverflow by the way. It has less overhead and is way simpler.
This variant will not return true for Guid, DateTimeOffset and possibly others.
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Thank you!