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Bookshelf.js/Knex.js innerJoin withRelated
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var Promise = require('bluebird'), | |
User = require('./user'), | |
knex, query; | |
knex = User.prototype._builder(User.prototype.tableName); | |
query = function (q) { | |
q.distinct() | |
.innerJoin('orders', function () { | |
this.on('users.id', '=', 'orders.user_id') | |
.andOn('orders.amount', '>', 100); | |
}) | |
.innerJoin('addresses', function () { | |
this.on('users.id', '=', 'addresses.user_id') | |
.andOn('addresses.state', '=', 'New York'); | |
}); | |
return q; | |
}; | |
Promise.all([ | |
query(knex.count()).first().then(function (row) { | |
return +row.count; | |
}), | |
User.query(query).fetchAll({ withRelated: ['orders', 'addresses'] }) | |
]).spread(function (count, users) { | |
// success | |
}); |
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var Promise = require('bluebird'); | |
Model.countAndFetch = function (query, options) { | |
return Promise.all([ | |
query(knex.count()).first().then(function (row) { | |
return +row.count; | |
}), | |
this.query(query).fetchAll(options) | |
]); | |
}; |
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User.query(function (q) { | |
q.distinct() | |
.innerJoin('orders', function () { | |
this.on('users.id', '=', 'orders.user_id') | |
.andOn('orders.amount', '>', 100); | |
}) | |
.innerJoin('addresses', function () { | |
this.on('users.id', '=', 'addresses.user_id') | |
.andOn('addresses.state', '=', 'New York'); | |
}); | |
}) | |
.fetchAll({ withRelated: ['orders', 'addresses'] }) | |
.then(function (users) { | |
var user = users.at(0), | |
orders = user.related('orders'), | |
addresses = user.related('addresses'); | |
// do stuff with the user, their orders, and their addresses | |
}); |
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Solution I've found: .andOn('code.searchcode', '=', bookshelf.knex.raw("'" + code + "'"));