Created
November 17, 2017 10:08
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AP1 2017-11-17 Ordenació 3
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#include <iostream> | |
#include <vector> | |
#include <algorithm> | |
#include <cstdlib> | |
#include <ctime> | |
#include <cassert> | |
using namespace std; | |
double now() { | |
return clock() / double(CLOCKS_PER_SEC); | |
} | |
void merge(vector<double>& v, int i, int m, int j) { | |
vector<double> r; | |
int i1 = i; | |
int i2 = m+1; | |
while (i1 <= m and i2 <= j) { | |
if (v[i1] <= v[i2]) { | |
r.push_back(v[i1]); | |
++i1; | |
} else { | |
r.push_back(v[i2]); | |
++i2; | |
} | |
} | |
while (i1 <= m) { | |
r.push_back(v[i1]); | |
++i1; | |
} | |
while (i2 <= j) { | |
r.push_back(v[i2]); | |
++i2; | |
} | |
for (int i3 = i; i3 <= j; ++i3) { | |
v[i3] = r[i3 - i]; | |
} | |
} | |
void mergesort(vector<double>& v, int i, int j) { | |
if (i < j) { | |
int m = (i+j) / 2; | |
mergesort(v, i, m); | |
mergesort(v, m+1, j); | |
merge(v, i, m, j); | |
} | |
} | |
void ordena_per_fusio(vector<double>& v) { | |
mergesort(v, 0, v.size() - 1); | |
} | |
int main() { | |
srand(time(0)); | |
int n; | |
cin >> n; | |
vector<double> v(n); | |
for (int i = 0; i < n; ++i) { | |
v[i] = rand() / double(RAND_MAX); | |
} | |
double t1 = now(); | |
ordena_per_fusio(v); | |
double t2 = now(); | |
cout << t2 - t1 << endl; | |
for (int i = 0; i < n-1; ++i) { | |
assert(v[i] <= v[i+1]); | |
} | |
} |
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Exercici: A la solució feta a classe, el vector
r
comença buit i se li van posant els elements al final ambpush_back
. Modifiqueu el codi per crear el vector de la mida adequada i no ferpush_back
s.