Created
April 10, 2012 08:31
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Code to count card combinations according to this math.SE question: http://math.stackexchange.com/questions/129580
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import java.util.ArrayList; | |
import java.util.List; | |
public class Question129580 { | |
static List<int []> getPermutations (int n) { | |
return getPermutations (n,n); | |
} | |
static List<int []> getPermutations (int n,int k) { | |
List<int []> permutations = new ArrayList<int[]> (); | |
makePermutations (permutations,new int [k],new boolean [n],0); | |
return permutations; | |
} | |
static void makePermutations (List<int []> permutations,int [] permutation,boolean [] used,int j) { | |
if (j == permutation.length) | |
permutations.add (permutation.clone ()); | |
else | |
for (int i = 0;i < used.length;i++) | |
if (!used [i]) { | |
permutation [j] = i; | |
used [i] = true; | |
makePermutations (permutations,permutation,used,j + 1); | |
used [i] = false; | |
} | |
} | |
public static void main (String [] args) { | |
for (int n = 1;n <= 4;n++) { | |
int k = (n * (n + 1)) / 2; | |
int count = 0; | |
outer: | |
for (int [] p : Permutations.getPermutations (k)) { | |
for (int i = 0;i < n;i++) { | |
for (int j = (i * (i + 1)) / 2,l = 0;l < i;l++,j++) { | |
if (Math.abs (p [j] - p [j + 1]) == 1) | |
continue outer; | |
} | |
} | |
count++; | |
} | |
System.out.println (n + " : " + count); | |
} | |
} | |
} |
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