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@joshuastr
Created April 27, 2016 16:35
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list = {'yvr' => 'Vancouver', 'yba' => 'Banff', 'yyz' => 'Toronto', 'yxx' => 'Abbotsford', 'ybw' => 'Calgary'}
# Why is it returning nil instead of first element of the list above
puts list.first
def average(numbers)
sum = 0
if numbers.empty?
return nil
end
numbers.each do |num|
sum += num.to_i
end
sum.to_f / numbers.size
end
## TEST HELPER METHOD
def test_average(array = nil)
print "avg of #{array.inspect}:"
result = average(array)
p result
end
## TEST CODE
test_average([4,5,6]) # => 5
test_average([15,5,10]) # => 10
# Should treat string like number
test_average([15,'5',10]) # => 10
# Should show decimal value
test_average([10, 5]) # => 7.5 instead of just 7
# Watch out! Even tests can have bugs!
test_average([9, 5, 7])
# Empty set should return nil, not throw an error
test_average([]) # => nil
# Non-existent set should return nil
test_average() # => nil
# BONUS: Should ignore nils in the set
#test_average([9,6,nil,3]) # => 6
def sum(list)
sum = 0
list.each do |ele|
sum += ele
end
sum
end
list1 = [16,21,31,42,55]
# 1. The following should return 165 instead of an error
puts sum(list1)
# 2. How would you refactor it using an enumerable method other than each? Examples of enumerables: map, select, inject, reject, detect.
def sum1(list)
sum = 0
list.map{|n| sum += n}
sum
end
puts sum1(list)
def char_count(list)
letters = {}
list.each do |word|
word.split('').each { |letter|
if letters[letter].nil?
letters[letter] = 1
else
letters[letter] += 1
end }
end
letters
end
puts char_count(['apples', 'oranges', 'hipsters', 'are', 'same'])
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