javascript conversion from ip address to long integer and vice versa

int2ip.js

function int2ip (ipInt) {
    return ( (ipInt>>>24) +'.' + (ipInt>>16 & 255) +'.' + (ipInt>>8 & 255) +'.' + (ipInt & 255) );
}

ip2int.js

function ip2int(ip) {
    return ip.split('.').reduce(function(ipInt, octet) { return (ipInt<<8) + parseInt(octet, 10)}, 0) >>> 0;
}

Hi,
I've used both of your function, which converted "original_int -1062731546" to "converted ip 192.168.0.230"
Then I tried to reverse but it gave me "converted int 3232235750" instead of "-1062731546",
Here is the link to demo: https://stackblitz.com/edit/js-1ccktx

These methods don't work right, -1062731546 is correct, I'm just digging into this now, so I am not an expert, but anything over 128.0.0.0 goes into the negative space for 32 bit and would set the negative bit. or something like that.

The methods do work correctly. -1062731546 as well as 3232235750 are a correct integer representation of the IP address 192.168.0.230. In binary, they're the exact same, but depending on whether you look at the value as signed integer (then the first bit means "negative value" and the remaining 31 bits mean 1062731546) or unsigned (then the 32 bits mean 3232235750).

>>> 0 in the ip2int function ensures a conversion to unsigned int. Removing it turns the result into the negative value you were looking for:

// 3232235750
'192.168.0.230'.split('.').reduce(function(ipInt, octet) { return (ipInt<<8) + parseInt(octet, 10)}, 0) >>> 0; 

// -1062731546
'192.168.0.230'.split('.').reduce(function(ipInt, octet) { return (ipInt<<8) + parseInt(octet, 10)}, 0);  

@filecage

Would it not be shorter then to to replace <<8 with * 256 ?
It seems like the >>> 0 is then obsolete.

'192.168.0.230'.split('.').reduce(function(ipInt, octet) { return (ipInt * 256) + parseInt(octet, 10)}, 0); 
// 3232235750

@elovin indeed, it is!

My example was to explain the difference between the two methods because someone was confused with the negative value being incorrect, which I demonstrated is not true. :)