Created
June 25, 2011 21:21
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Y.when with end()
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| // In this case async3() won't be executed instantly but rather after async1 and async2 are completed | |
| Y.when(async1(), async2()).then(async3()).end(function () { | |
| console.log('success'); | |
| }, function () { | |
| console.log('failure'); | |
| }); |
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