Read XML file from resources directory and deserialize it into POJO using Jackson

App.java

public class App {
  public static void main(String[] args) {
    record User(String id, String name) {}
    var reader = XmlResourceReader.create(User.class);
    // src/main/resources/files/user.xml
    reader.read("files/user.xml")
      .ifPresent(user -> System.out.pritnln(user.id() + " " + user.name()));
  }
}

XmlResourceReader.java

import com.fasterxml.jackson.dataformat.xml.XmlMapper;

import java.io.IOException;
import java.util.Optional;

public final class XmlResourceReader<T> {
    private final Class<T> model;

    private XmlResourceReader(Class<T> model) {
        this.model = model;
    }

    public static <T> XmlResourceReader<T> create(Class<T> model) {
        return new XmlResourceReader<>(model);
    }

    public Optional<T> read(String fileName) {
        var classLoader = this.getClass().getClassLoader();
        var inputStream = classLoader.getResourceAsStream(fileName);

        try {
            return Optional.of(new XmlMapper().readValue(inputStream, this.model));
        } catch (IOException e) {
            e.getStackTrace();
            return Optional.empty();
        }
    }
}