justaguywhocodes · April 7, 2022 21:38
diff --git a/cistern.txt b/cistern.txt
 A cistern.
 The height is 3.33, and a volume of 27.78 has been excavated.
 The length exceeds the width by 0.83.
 You should take the reciprocal of the height, 3.33, obtaining 0.3.
 Multiplay this by the volume, 27.78, obtaining 8.33.
 Take half of 0.83 and square it, obtaining 0.17.
 Add 8.33 and you get 8.51.
 The square root is 2.92.
 Make two copies of this, adding to the one 0.42 and subtracting from the other.
 You find that 3.33 is the length and 2.5 is the width.
 Thisis the procedure.
	A cistern.
	The height is 3.33, and a volume of 27.78 has been excavated.
	The length exceeds the width by 0.83.
	You should take the reciprocal of the height, 3.33, obtaining 0.3.
	Multiplay this by the volume, 27.78, obtaining 8.33.
	Take half of 0.83 and square it, obtaining 0.17.
	Add 8.33 and you get 8.51.
	The square root is 2.92.
	Make two copies of this, adding to the one 0.42 and subtracting from the other.
	You find that 3.33 is the length and 2.5 is the width.
	Thisis the procedure.