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How to iterate neighbors of a grid efficiently and concisely.
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#include <algorithm> | |
template <typename I> | |
void rotate_2d(I& a, I& b) { | |
std::swap(a, b); | |
b = -b; | |
} | |
int main() { | |
// Suppose we want to iterate over the neighbors of a cell in a 2D grid: | |
// * * * | |
// * - * | |
// * * * | |
// This can be done with the following loop: | |
printf("diagonal\n"); | |
for (int i = -1; i <= 1; ++i) { | |
for (int j = -1; j <= 1; ++j) { | |
if (i == j) continue; | |
printf("%d, %d\n", i, j); | |
} | |
} | |
// But what if just want the directly adjacent cells and ignore diagonal cells? | |
// * | |
// * - * | |
// * | |
// This is a little tricker, but the idea is just to | |
// rotate one neighbor around the center cell, 4 times. | |
printf("square\n"); | |
{ | |
int i = 1; | |
int j = 0; | |
for (int k = 0; k < 4; ++k) { | |
printf("%d, %d\n", i, j); | |
rotate_2d(i, j); | |
} | |
} | |
} |
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