Reimplementing the swift if statement without using the if keyword

if-without-if.swift

func _if_without_if(condition: BooleanType, action: () -> ()) {
    // We fake the false case by using an empty closure, e.g a NOP
    let actions = [{}, action]

    // boolValue returns a Bool and we can abuse the fact that
    // hashValue of true is 1 and then hashValue of false is 0 to
    // get the correct closure to run
    actions[condition.boolValue.hashValue]()
}

_if_without_if(1 < 2) {
    println("1 is less than 2 even without if")
}