BambooFox CTF 2021 - The Vault

Given a webpage displaying a keypad index.html, javascript driver file main.js and webassembly compiled binary wasm, you are supposed to find the pin that unlocks the vault.

Blackbox approach

Without dealing with the wasm binary at first, reading through main.js specifically between lines 18 and 25 there seems to be some environment validations and checks.

var ENVIRONMENT_IS_WEB = false;
var ENVIRONMENT_IS_WORKER = false;
var ENVIRONMENT_IS_NODE = false;
var ENVIRONMENT_IS_SHELL = false;
ENVIRONMENT_IS_WEB = typeof window === 'object';
ENVIRONMENT_IS_WORKER = typeof importScripts === 'function';
ENVIRONMENT_IS_NODE = typeof process === 'object' && typeof process.versions === 'object' && typeof process.versions.node === 'string';
ENVIRONMENT_IS_SHELL = !ENVIRONMENT_IS_WEB && !ENVIRONMENT_IS_NODE && !ENVIRONMENT_IS_WORKER;

Which lead me to think, possibly the driver code main.js supports multiple environments, indeed running the code with nodejs yields the banner.

kaftejiman:~/rev/vault/upload
▶ node main.js
 WASM VAULT v0.1

which comes from:

function banner() {
    console.log("%c WASM VAULT v0.1", "font-weight: bold; font-size: 50px;color: red; text-shadow: 3px 3px 0 rgb(217,31,38) , 6px 6px 0 rgb(226,91,14) , 9px 9px 0 rgb(245,221,8) , 12px 12px 0 rgb(5,148,68) , 15px 15px 0 rgb(2,135,206) , 18px 18px 0 rgb(4,77,145) , 21px 21px 0 rgb(42,21,113)")
}

knowing _validate is the bridge function to the checking routine in the wasm binary:

var _validate = Module["_validate"] = function () {
    return (_validate = Module["_validate"] = Module["asm"]["n"]).apply(null, arguments)
};

for the sake of carrying purely a black box approach, we can simply try to bruteforce all possible combinations (supposed 4 characters long) by slightly modifying the main.js code, specifically:

modifying banner function to make it call the checking routine
modifying fail function to make it less verbose (simply null it)
modifying get_password function to make it read pin from argv

function banner() {
    console.log('trying: '+process.argv[2]);
    _validate();
}

function fail() {
}

function get_password() {
    const val = process.argv[2];
    const len = lengthBytesUTF8(val) + 1;
    const str = _malloc(len);
    stringToUTF8(val, str, len);
    return str
}

function win(flag) {
    console.log('found');
    console.log(`${UTF8ToString(flag)}`);
}

with some bash wrapper (albeit naive algorithm):

for i in `seq 040 177`
do
    for j in `seq 040 177`
    do
        for k in `seq 040 177`
        do
            for l in `seq 040 177`
            do
                    c1=$(printf "\\$(printf %o $i)\n")
                    c2=$(printf "\\$(printf %o $j)\n")
                    c3=$(printf "\\$(printf %o $k)\n")
                    c4=$(printf "\\$(printf %o $l)\n")
                    node main.js "${c1}${c2}${c3}${c4}"
            done
                
        done
            
    done
        
done

let it spin, after a while you get:

▶ ./xx.sh
.
.
.
.
trying: p/k0
trying: p0k0
trying: p1k0
trying: p2k0
trying: p3k0
found
flag{w45m_w4sm_wa5m_wasm}

White box approach

From the main.js specifically _evaluate() calling Module["asm"]["n"] we can deduce n() is probably the checking routine in the wasm binary.

Using wasm-decompile from wabt

▶ wasm-decompile main.wasm | grep -A28 'function n'
export function n() {
  var c:int;
  var a:{ a:long, b:long, c:long, d:short } = g_a - 32;
  g_a = a;
  var b:{ a:ubyte, b:ubyte, c:ubyte, d:ubyte } = a_d();
  a.d = d__WD_l4GoR[12]:ushort;
  a.c = d__WD_l4GoR[2]:long;
  a.b = d__WD_l4GoR[1]:long;
  a.a = d__WD_l4GoR[0]:long;
  if (f_h(b) != 4) goto B_b;
  if (b.a != 112) goto B_b;
  if (b.b != 51) goto B_b;
  if (b.c != 107) goto B_b;
  if (b.d != 48) goto B_b;
  var d:int = 22;
  var e:int = a;
  loop L_c {
    e[0]:byte = (b + (c & 3))[0]:ubyte ^ d;
    e = a + (c = c + 1);
    d = e[0]:ubyte;
    if (d) continue L_c;
  }
  a_c(a);
  goto B_a;
  label B_b:
  a_b();
  label B_a:
  g_a = a + 32;
}

with:

a_d() reads pin
a_c() spits flag
a_b() fail
f_h() sort of checksum maybe?

deduced from:

var asmLibraryArg = {
    'e': banner,
    'a': _emscripten_resize_heap,
    'b': fail,
    'd': get_password,
    'c': win
};

var b:{ a:ubyte, b:ubyte, c:ubyte, d:ubyte } = a_d();

b populated with pin: {a: 1st char, b:2nd char, c:3rd char, d:4th char}

actual pin check is carried here:

  if (b.a != 112) goto B_b;
  if (b.b != 51) goto B_b;
  if (b.c != 107) goto B_b;
  if (b.d != 48) goto B_b;

evaluate:

kaftejiman:RE/rev  master ✔                                                                              4d
▶ pypy3
Python 3.6.9 (2ad108f17bdb, Apr 07 2020, 02:59:05)
[PyPy 7.3.1 with GCC 7.3.1 20180303 (Red Hat 7.3.1-5)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>>> chr(112)+chr(51)+chr(107)+chr(48)
'p3k0'

try it:

▶ node main.js p3k0
trying: p3k0
found
flag{w45m_w4sm_wa5m_wasm}

done.

kaftejiman/bambooctf_vault.md

BambooFox CTF 2021 - The Vault

Blackbox approach

White box approach