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;定义一个接受一系列数字的函数,并在若且唯若每一对(pair)数字的差为一时,返回真,使用 ;(a) 递归 ;(b) do
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;http://acl.readthedocs.org/en/latest/zhCN/ch5-cn.html#chapter-5-exercises | |
;定义一个接受一系列数字的函数,并在若且唯若每一对(pair)数字的差为一时,返回真,使用 | |
;(a) 递归 | |
;(b) do | |
(defun linked-r (lst) | |
(or (null lst) | |
(null (cdr lst)) | |
(and (diff-1 (car lst) (cadr lst)) | |
(linked-r (cdr lst))))) | |
(defun linked-do (lst) | |
(let ((r t)) | |
(do ((rest (cdr lst) (cdr rest)) | |
(i (car lst) (car rest)) | |
(j nil i)) | |
((null i) 'done) | |
(unless (or (null i) | |
(null j) | |
(diff-1 i j)) | |
(setf r nil)) | |
) | |
r)) | |
(defun diff-1 (a b) | |
(or (eql a (+ b 1)) | |
(eql b (+ a 1)))) |
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