Created
January 11, 2014 15:36
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If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total. If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?
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singleDigits = ["zero","one","two","three","four","five","six","seven","eight","nine"] | |
tens = ["zero","ten","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"] | |
teens = ["zero"] * 11 + ["eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"] | |
hundredLength = len("hundred") | |
andLength = len("and") | |
singleDigits = [len(x) for x in singleDigits] | |
tens = [len(x) for x in tens] | |
teens = [len(x) for x in teens] | |
lengths = [] | |
def getLength(number): | |
isTeen = False | |
originalNumber = number | |
l = [] | |
if number / 100 > 0: | |
l.append(singleDigits[number/100]) | |
l.append(hundredLength) | |
number = number % 100 | |
if number > 0: | |
l.append(andLength) | |
if number / 10 > 0: | |
if number < 20 and number > 10: | |
l.append(teens[number]) | |
isTeen = True | |
number = number % 10 | |
else: | |
l.append(tens[number/10]) | |
number = number % 10 | |
if number > 0 and not isTeen: | |
l.append(singleDigits[number]) | |
return sum(l) | |
for number in xrange(1, 1000): | |
lengths.append(getLength(number)) | |
lengths.append(len("one")) | |
lengths.append(len("thousand")) | |
print sum(lengths) |
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