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IsPalindrome JavaScript SinglyLinkedList
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Node = function(char){ | |
this.char = char; | |
}; | |
Node.prototype = { | |
createNext: function(char){ | |
this.next = new Node(char); | |
return this.next; | |
} | |
} | |
var asLinkedList = function(subject){ | |
var head = new Node(subject[0]); | |
var current = head; | |
var i = 1; | |
while(i < subject.length){ | |
current = current.createNext(subject[i++]); | |
} | |
return head; | |
} | |
var reverseLink = function(node){ | |
var previous = null; | |
while (true){ | |
next = node.next; | |
node.next = previous; | |
if (!next) return node; | |
previous = node; | |
node = next; | |
} | |
} | |
var mid = function(head){ | |
var mid = head; | |
var current = head; | |
var count = 0; | |
while(current.next != null && current.next.next != null){ | |
count++; | |
current = current.next.next; | |
mid = mid.next; | |
} | |
if ((count % 2) == 0) | |
mid = mid.next; | |
return mid; | |
} | |
var isPalindrome = function(head) { | |
tail = reverseLink(mid(head)) | |
while (tail.char == head.char){ | |
if (tail.next == null|| head.next == null){ | |
return true; | |
} | |
tail = tail.next; | |
head = head.next; | |
} | |
return tail; | |
} | |
console.debug(isPalindrome(asLinkedList("aaa"))); | |
console.debug(isPalindrome(asLinkedList("abccba"))); | |
console.debug(isPalindrome(asLinkedList("lonnol"))); | |
console.debug(isPalindrome(asLinkedList("bob"))); | |
console.debug(isPalindrome(asLinkedList("1001"))); | |
console.debug(isPalindrome(asLinkedList("Igor"))); |
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