PYTHON: unzip all files in a directory

unzip_all.py

#!/usr/bin/python
import os, zipfile

for filename in os.listdir("."):
    if filename.endswith(".zip"):
        print filename
        name = os.path.splitext(os.path.basename(filename))[0]
        if not os.path.isdir(name):
            try:
                zip = zipfile.ZipFile(filename)
                os.mkdir(name)
                zip.extractall(path=name)
            except zipfile.BadZipfile, e:
                print "BAD ZIP: "+filename
                try:
                    os.remove(filename)
                except OSError as e: # this would be "except OSError, e:" before Python 2.6
                    if e.errno != errno.ENOENT: # errno.ENOENT = no such file or directory
                        raise # re-raise exception if a different error occured                

I have tried executing the code saving it as zipextractor.py. But it generated the following error although I mentioned the path correctly.

File "zipextractor.py", line 9, in
zip = zipfile.ZipFile(filename)
File "C:\Users\user\AppData\Local\Programs\Python\Python37\lib\zipfile.py", line 1204, in init
self.fp = io.open(file, filemode)
FileNotFoundError: [Errno 2] No such file or directory: '.............'