Ruby questions

Ruby challenge.rb

1) What does the following code print?
    p ["tommy", "chuckie"].map(&:upcase)
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2) Write a programe for this.
    colors = ['red', 'violet', 'blue']

    Use the colors array to construct the following array:
    [['red', 1], ['violet', 2], ['blue', 3]]
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3) Create an array of all the numbers between 1 and 100 that are divisible by both 3 and 5.

4) Write a programe for this.
music = [["blind melon", "no rain"], ["sublime", "40 oz to freedom"], ["damian marley", "jr gong"]]

Output:
Use the music array to construct the following hash:
{"blind melon" => "no rain", "sublime" => "40 oz to freedom", "damian marley" => "jr gong"}
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5) Create an array of all the elements that are in first, but not in second.

first = ["cool", "busta", "odb"]
second = ["puffy", "cool", "busta"]
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6) What does the following code print?

class Parent
  def status
    "I am happy"
  end
end

class Child < Parent
  def status
    "ARGH"
  end
end

p Child.new.status

1. What does the following code print?
   p ["tommy", "chuckie"].map(&:upcase)

Ans : ["TOMMIE", "CHUCKIE"]

2. Write a programe for this.
   colors = ['red', 'violet', 'blue']
   Use the colors array to construct the following array:

[['red', 1], ['violet', 2], ['blue', 3]]

Ans: res = [] ; ['red', 'violet', 'blue'].each_with_index{|a,i| res.push([a,i+1])}

3. Create an array of all the numbers between 1 and 100 that are divisible by both 3 and 5.
   Ans:
   arr = []
   100.times do|i|
   arr.push(i) if((i% 3 == 0) && (i%5 == 0))
   end

4. Write a programe for this.
   music = [["blind melon", "no rain"], ["sublime", "40 oz to freedom"], ["damian marley", "jr gong"]]
   Output:
   Use the music array to construct the following hash:

{"blind melon" => "no rain", "sublime" => "40 oz to freedom", "damian marley" => "jr gong"}

Ans: a = [["blind melon", "no rain"], ["sublime", "40 oz to freedom"], ["damian marley", "jr gong"]].flatten
h = HASH[*a]

5. Create an array of all the elements that are in first, but not in second.
   first = ["cool", "busta", "odb"]

second = ["puffy", "cool", "busta"]

Ans: Result = first - secound

6. Ans : "ARGH"

ANSWERS UPDATED WITH RESULT:

1. What does the following code print?
   p ["tommy", "chuckie"].map(&:upcase)
   Result : ["TOMMIE", "CHUCKIE"]

2. Write a programe for this.
   colors = ['red', 'violet', 'blue']
   Use the colors array to construct the following array:
   Ans: res = [] ; ['red', 'violet', 'blue'].each_with_index{|a,i| res.push([a,i+1])}
   Result : [["red", 1], ["violet", 2], ["blue", 3]]

3. Create an array of all the numbers between 1 and 100 that are divisible by both 3 and 5.
   Ans:
   arr = []
   100.times do|i|
   arr.push(i) if((i% 3 == 0) && (i%5 == 0))
   end
   Result : [0, 15, 30, 45, 60, 75, 90]

4. Write a programe for this.
   music = [["blind melon", "no rain"], ["sublime", "40 oz to freedom"], ["damian marley", "jr gong"]]
   Output:
   Use the music array to construct the following hash:
   {"blind melon" => "no rain", "sublime" => "40 oz to freedom", "damian marley" => "jr gong"}

Ans: a = [["blind melon", "no rain"], ["sublime", "40 oz to freedom"], ["damian marley", "jr gong"]].flatten
h = Hash[*a]
Result => {"blind melon"=>"no rain", "sublime"=>"40 oz to freedom", "damian marley"=>"jr gong"}

5. Create an array of all the elements that are in first, but not in second.
   first = ["cool", "busta", "odb"]second = ["puffy", "cool", "busta"]
   Ans : result = first - second
   Result => ["odb"]

6. Ans : "ARGH"