Share to Instagram

  func tappedInstagram(sharingOptionsView: SharingOptionsView) {
        Analytics().track(event: "Share Instagram")
        
        guard let instagramURL = URL(string: "instagram://app") else {return}
        if UIApplication.shared.canOpenURL(instagramURL) {
            
            guard let imageToShare = makeCompositeToShare() else { return }
            let imageData = UIImageJPEGRepresentation(imageToShare, 1.0)
            
            do {
                let fileURL = try FileManager.default.url(for: .documentDirectory, in: .userDomainMask, appropriateFor: nil, create: false).appendingPathComponent("image.igo")
                try imageData?.write(to: fileURL, options: .atomic)
                documentInteractionController.url = fileURL
                documentInteractionController.uti = "com.instagram.exclusivegram"
                documentInteractionController.presentOpenInMenu(from: view.bounds, in: view, animated: true)
            } catch {
                print(error)
                showAlertUnableToShareImage()
            }
        } else {
            showAlertUnableToShareImage()
        }
    }
    
    func showAlertUnableToShareImage() {
        let alertController = UIAlertController(title: nil, message: "Unable to open image in Instagram ", preferredStyle: .alert)
        let action = UIAlertAction(title: "OK", style: .default, handler: nil)
        alertController.addAction(action)
        present(alertController, animated: true, completion: nil)
    }