revisedLinearC++

revisedLinearC++

#include "stdafx.h"
#include <iostream>
using namespace std;


int main() 
{
	int x[17] = {7, 3, 32, 2, 55, 34, 6, 13, 29, 22, 11, 9, 1, 5, 42, 39, 8};
	int position = -1;
	int value = 0;

	// is below the best or most efficient way I could list the values one by one of the array x[17]?
	// does a shortcut like:
	// cout << "List = " << x[17] << endl;
	// exist?
	cout << "List = 7, 3, 32, 2, 55, 34, 6, 13, 29, 22, 11, 9, 1, 5, 42, 39, 8" << endl;

	cout << "Enter an integer in the list to search for: ";
	cin >> value;

	for(int i = 0; i <= (17 - 1); ++i)
	{
		if(x[i] == value)
		{
			// assign i to position.
			position = i;
			break;
		}
		else
		{
			continue;
		}
	}

	cout << "Item found at index [" << position << "]" << endl;
}