Created
August 17, 2012 12:52
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.map(parseInt) fails
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| ['1', '2'].map(parseInt) | |
| // output [1, NaN] | |
| ['1', '2'].map(Number) | |
| // output [1, 2] | |
| Why? |
dslming
commented
Aug 6, 2018
- when parseInt() receive second param, and this param is illegal, the result is fails.
- Function map() will send 3 params to parseInt, is value, index and array.
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