Get the queryset with the most results, for blackcross in #django IRC

blackcross.py

querysets = (
  Page.objects.filter(...),
  Something.objects.exclude(...),
  Etc.objects.filter(...),
)
results = {qs.count(): (index, qs) for index, qs in enumerate(querysets)}
best = max(results)
worst = min(results)
if best > 0:
  best_counts = results[best][1]
if worst > 0:
  worst_counts = results[worst][1]
# note you can also figure out what index gave you the best results by looking at [0]