Created
May 29, 2013 04:25
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Converting floating-point number to IEEE754 representation by using union and struct in c.
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#include <stdio.h> | |
/* | |
* See also : http://class.ece.iastate.edu/arun/CprE281_F05/ieee754/ie5.html | |
*/ | |
union FloatingPointIEEE754 { | |
struct { | |
unsigned int mantissa : 23; | |
unsigned int exponent : 8; | |
unsigned int sign : 1; | |
} raw; | |
float f; | |
} number; | |
int main() { | |
number.f = -6.8; | |
printf("%x, %x, %x", number.raw.mantissa, number.raw.exponent, number.raw.sign ); | |
return 0; | |
} |
Can i do the bitwise operation on these unsignes integers now?
I have to vanish some bits of mantissa... How can i do this?
Not pretty, but I came up with this one to properly display the number. @kamalhyder
#include <stdio.h>
#define BYNARY_FMT "%u%u%u%u%u%u%u%u"
#define BYTE_TO_BIN(b) ((b) & 0x80 ? 1 : 0),\
((b) & 0x40 ? 1 : 0),\
((b) & 0x20 ? 1 : 0),\
((b) & 0x10 ? 1 : 0),\
((b) & 0x08 ? 1 : 0),\
((b) & 0x04 ? 1 : 0),\
((b) & 0x02 ? 1 : 0),\
((b) & 0x01 ? 1 : 0)
#define BIT_FMT "%u"
#define NTH_BIT(b, n) ((b) & (1 << n) ? 1 : 0)
union FloatingPointIEEE754 {
struct {
unsigned int m: 23;
unsigned int e: 8;
unsigned int s: 1;
} raw;
float f;
} ieee754;
int main() {
ieee754.f = -6.8;
printf(
BIT_FMT " "
BYNARY_FMT " "
BIT_FMT BIT_FMT BIT_FMT BIT_FMT BIT_FMT BIT_FMT BIT_FMT BYNARY_FMT BYNARY_FMT "\n\n",
// SIGN
NTH_BIT (ieee754.raw.s , 0),
// EXPONENT
BYTE_TO_BIN(ieee754.raw.e ),
// MANTISSA
NTH_BIT (ieee754.raw.m >> 16, 6),
NTH_BIT (ieee754.raw.m >> 16, 5),
NTH_BIT (ieee754.raw.m >> 16, 4),
NTH_BIT (ieee754.raw.m >> 16, 3),
NTH_BIT (ieee754.raw.m >> 16, 2),
NTH_BIT (ieee754.raw.m >> 16, 1),
NTH_BIT (ieee754.raw.m >> 16, 0),
BYTE_TO_BIN(ieee754.raw.m >> 8 ),
BYTE_TO_BIN(ieee754.raw.m )
);
return 0;
}
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i have a question, ¿How to 64 bits?
Its ok:
struct { unsigned long long mantissa : 52; unsigned short int exponent : 11; unsigned int sign : 1; }doublePrecision;