Created
April 22, 2015 22:58
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LagNonZero_CExample
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#include <iostream> | |
#include <sys/time.h> // for gettimeofday() | |
using namespace std; | |
double r2() | |
{ | |
return (double)rand() / (double)RAND_MAX ; | |
} | |
int main() { | |
long iter, i; | |
double x; | |
double elapsedTime; | |
double *v; | |
double LastVal; | |
timeval t1, t2; | |
iter = 100000000; | |
v = (double *)malloc(sizeof(*v)*iter); | |
for ( i = 0; i < iter; i++ ) | |
{ | |
x = r2(); | |
if ( x > 0.5) | |
{ | |
v[i] = x; | |
} | |
else | |
{ | |
v[i] = 0; | |
} | |
} | |
// start timer | |
gettimeofday(&t1, NULL); | |
// do stuff | |
LastVal = 0; | |
for ( i = 0; i < iter; i++ ) | |
{ | |
if ( v[i] == 0) | |
{ | |
v[i] = LastVal; | |
} | |
else | |
{ | |
LastVal = v[i]; | |
} | |
} | |
// stop timer | |
gettimeofday(&t2, NULL); | |
// compute and print the elapsed time in millisec | |
elapsedTime = (t2.tv_sec - t1.tv_sec) * 1000.0; // sec to ms | |
elapsedTime += (t2.tv_usec - t1.tv_usec) / 1000.0; // us to ms | |
cout << elapsedTime << " ms.\n"; | |
for ( i = 0; i < iter; i++ ) | |
{ | |
if ( v[i] == 0 ) | |
{ | |
printf("v[%lu] = %f\n", i , v[i]); | |
} | |
} | |
return 0; | |
} |
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