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October 23, 2015 09:24
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AOJ0530 Pyon-Pyon River Crossing
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#include <bits/stdc++.h> | |
using namespace std; | |
typedef long long int ll; | |
typedef pair<int, int> P; | |
typedef pair<ll, ll> Pll; | |
typedef vector<int> Vi; | |
typedef tuple<int, int, int> T; | |
#define FOR(i,s,x) for(int i=s;i<(x);i++) | |
#define REP(i,x) FOR(i,0,x) | |
#define ALL(c) c.begin(), c.end() | |
#define DUMP( x ) cerr << #x << " = " << ( x ) << endl | |
const int INF = 1<<29; | |
int dp[150][10][77]; | |
int stones[150][10][2]; | |
int col[150]; | |
int main() { | |
// use scanf in CodeForces! | |
cin.tie(0); | |
ios_base::sync_with_stdio(false); | |
while (true) { | |
int N, M; | |
cin >> N >> M; | |
if (N == 0 && M == 0) break; | |
REP(i, N) { | |
cin >> col[i]; | |
REP(j, col[i]) { | |
cin >> stones[i][j][0] >> stones[i][j][1]; | |
} | |
} | |
REP(i, N) REP(j, col[i]) REP(k, M+1) dp[i][j][k] = INF; | |
REP(j, col[0]) dp[0][j][0] = 0; | |
REP(j, col[1]) dp[1][j][1] = 0; | |
REP(i, N-1) { | |
REP(j, col[i]) { | |
int x_now = stones[i][j][0], d_now = stones[i][j][1]; | |
REP(m, M+1) { | |
if (dp[i][j][m] == INF) continue; | |
REP(k, col[i+1]) { | |
dp[i+1][k][m] = min(dp[i+1][k][m], dp[i][j][m] + (d_now + stones[i+1][k][1]) * abs(x_now - stones[i+1][k][0])); | |
} | |
if (i < N-2 && m < M) { | |
REP(k, col[i+2]) { | |
dp[i+2][k][m+1] = min(dp[i+2][k][m+1], dp[i][j][m] + (d_now + stones[i+2][k][1]) * abs(x_now - stones[i+2][k][0])); | |
} | |
} | |
} | |
} | |
} | |
int ans = INF; | |
REP(j, col[N-1]) REP(m, M+1) ans = min(ans, dp[N-1][j][m]); | |
REP(j, col[N-2]) REP(m, M) ans = min(ans, dp[N-2][j][m]); | |
cout << ans << endl; | |
} | |
return 0; | |
} |
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