Define a function max() that takes two numbers as arguments and returns the largest of them. Use the if-then-else construct available in Javascript.

max.js

// Define a function max() that takes two numbers as
// arguments and returns the largest of them. Use the
// if-then-else construct available in Javascript.
// https://jsfiddle.net/ryjtyomv/

function max(firstNum, secondNum){
  
    if (firstNum > secondNum) {
       console.log(firstNum + " is larger than " + secondNum);
    } else {
        console.log(firstNum + " is less than " + secondNum);
    }
    return;
  
}

// Lets set two numbers
max(142,234);

Thanks man for the idea. I just caught it.