Simple Python3 HTTP Server; one-line python GET method

python3_http_simple_server.py

from http.server import BaseHTTPRequestHandler, HTTPServer
from urllib.parse import urlparse
import subprocess

class GetHandler(BaseHTTPRequestHandler):

    ls_l_cmd = ['ls','-l']

    def do_GET(self):
        parsed_path = urlparse(self.path)
        cons_res = subprocess.run(GetHandler.ls_l_cmd, stdout=subprocess.PIPE)
        message = '\n'.join([
            'Simple Python3 HTTP server',
	        'ls -l command result: \n %s' % cons_res.stdout,
            '',
            ]).replace('\\n', '\n')
        self.send_response(200)
        self.end_headers()
        message_bytes = str.encode(message)
        self.wfile.write(message_bytes)
        return

if __name__ == '__main__':
    from http.server import HTTPServer
    server = HTTPServer(('localhost', 8080), GetHandler)
    print ('Starting server at http://localhost:8080')
    server.serve_forever()

If you don't have Python installed:

macOS:
brew install python3

ubuntu:
sudo apt install python3

Python2 verion available here