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@kosugi
Created October 19, 2011 04:58
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FizzBuzz
# -*- coding: utf-8 -*-
fb = ((lambda n: str(n), lambda n: 'Buzz'), (lambda n: 'Fizz', lambda n: 'FizzBuzz'))
for n in range(1, 101):
print fb[n % 3 == 0][n % 5 == 0](n)
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