Created
February 14, 2014 19:13
-
-
Save kosugi/9007121 to your computer and use it in GitHub Desktop.
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| # -*- coding: utf-8 -*- | |
| # http://www.checkio.org/mission/brackets/ | |
| # 普通こうでは!? | |
| from itertools import dropwhile | |
| pairs = '{} [] ()'.split() | |
| def parse_term(s): | |
| t = ''.join(dropwhile(str.isdigit, s)) | |
| if s != t: | |
| return t | |
| for pair in pairs: | |
| if t[0] == pair[0]: | |
| t = parse_expr(t[1:]) | |
| if t[0] == pair[1]: | |
| return t[1:] | |
| raise Exception('term') | |
| def parse_expr(s): | |
| s = parse_term(s) | |
| while True: | |
| if s == '' or s[0] not in '+-/*': | |
| return s | |
| s = parse_term(s[1:]) | |
| def checkio(s): | |
| try: | |
| if '' == parse_expr(s): | |
| return True | |
| except: | |
| pass | |
| return False | |
| checkio("((5+3)*2+1)") == True | |
| checkio("{[(3+1)+2]+}") == False | |
| checkio("(3+{1-1)}") == False | |
| checkio("[1+1]+(2*2)-{3/3}") == True | |
| checkio("(({[(((1)-2)+3)-3]/3}-3)") == False |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment