Created
November 11, 2011 05:01
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newtonRaphson method
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| ## module error | |
| ''' err(string). | |
| Prints 'string' and terminates program. | |
| ''' | |
| import sys | |
| def err(string): | |
| print string | |
| raw_input('Press return to exit') | |
| sys.exit() | |
| ## module newtonRaphson | |
| ''' root = newtonRaphson(f,df,a,b,tol=1.0e-9). | |
| Finds a root of f(x) = 0 by combining the Newton-Raphson | |
| method with bisection. The root must be bracketed in (a,b). | |
| Calls user-supplied functions f(x) and its derivative df(x). | |
| ''' | |
| def newtonRaphson(f, df, a, b, tol=1.0e-9): | |
| # import error | |
| fa = f(a) | |
| if fa == 0.0: return a | |
| fb = f(b) | |
| if fb == 0.0: return b | |
| if fa * fb > 0.0: err('Root is not bracketed') | |
| x = 0.5 * (a + b) | |
| for i in range(30): | |
| fx = f(x) | |
| if abs(fx) < tol: return x | |
| # Tighten the brackets on the root | |
| if fa * fx < 0.0: | |
| b = x | |
| else: | |
| a = x | |
| # Try a Newton-Raphson step | |
| dfx = df(x) | |
| # If division by zero, push x out of bounds | |
| try: dx = -fx / dfx | |
| except ZeroDivisionError: dx = b - a | |
| x = x + dx | |
| # If the result is outside the brackets, use bisection | |
| if (b - x) * (x - a) < 0.0: | |
| dx = 0.5 * (b - a) | |
| x = a + dx | |
| # Check for convergence | |
| if abs(dx) < tol * max(abs(b), 1.0): return x | |
| print 'Too many iterations in Newton-Raphson' | |
| def f(x): | |
| return x**3 - 10*x**2 + 5 | |
| def df(x): | |
| return 3*x - 20*x | |
| solution = newtonRaphson(f, df, 0.1, 1, tol=1e-11) | |
| print solution |
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