Upload stream

Example.cs

[HttpPost, Route("project/{projectId}/folder/{folderId}/upload")]
public async Task<object> UploadFile(string projectId, string folderId)
{
    var request = Request;

    // This solution was provided by: http://www.asp.net/web-api/overview/advanced/sending-html-form-data-part-2
    // Check if the request contains multipart/form-data.
    if (!Request.Content.IsMimeMultipartContent())
    {
        throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
    }

    string root = HttpContext.Current.Server.MapPath("~/App_Data");
    var provider = new MultipartFormDataStreamProvider(root);

    try
    {
        // Read the form data.
        await Request.Content.ReadAsMultipartAsync(provider);

        // This illustrates how to get the file names.
        foreach (MultipartFileData file in provider.FileData)
        {
            var realName = file.Headers.ContentDisposition.FileName.Replace("\"", "");
            var tempUploadName = file.LocalFileName;
            await Projects.HandleStagedFile(projectId, folderId, tempUploadName, realName);
        }

        return Request.CreateResponse(HttpStatusCode.OK);
    }
    catch (Exception e)
    {
        return Request.CreateErrorResponse(HttpStatusCode.InternalServerError, e);
    }

    return new {status = "OK"};
}