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2D Range Tree Query Example
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/* | |
LANG: C++ | |
*/ | |
#include <iostream> | |
#include <cstdio> | |
using namespace std; | |
#define MAXN 512 | |
int RA, RB, RM; | |
int next_rand() { | |
static int RS = 0; | |
return RS = (1ll * RA * RS + RB) % RM; | |
} | |
int A[MAXN*2][MAXN*2]; | |
int get_c(int x, int y, int CA, int CB, int QCA, int QCB) { | |
if(QCB <= CA || CB <= QCA) return 0; | |
if(QCA <= CA && CB <= QCB) { | |
return A[x][y]; | |
} | |
int CM = CA + (CB - CA) / 2; | |
return max(get_c(x, 2 * y, CA, CM, QCA, QCB), | |
get_c(x, 2 * y + 1, CM, CB, QCA, QCB)); | |
} | |
int get_r(int x, int RA, int RB, int QRA, int QRB, int QCA, int QCB) { | |
if(QRB <= RA || RB <= QRA) return 0; | |
if(QRA <= RA && RB <= QRB) { | |
return get_c(x, 1, 0, MAXN, QCA, QCB); | |
} | |
int RM = RA + (RB - RA) / 2; | |
return max(get_r(x * 2, RA, RM, QRA, QRB, QCA, QCB), | |
get_r(x * 2 + 1, RM, RB, QRA, QRB, QCA, QCB)); | |
} | |
int main() { | |
int N, Q, M; scanf("%d%d%d", &N, &Q, &M); | |
for(int k = 0; k < M; k++) { | |
int r1, c1, r2, c2; | |
scanf("%d%d%d%d", &r1, &c1, &r2, &c2); | |
r1--; c1--; r2--; c2--; | |
for(int i = r1; i <= r2; i++) { | |
for(int j = c1; j <= c2; j++) { | |
int x; | |
scanf("%d", &x); | |
A[MAXN + i][MAXN + j] += x; | |
} | |
} | |
} | |
for(int i = 2 * MAXN - 1; i; i--) { | |
for(int j = 2 * MAXN - 1; j; j--) { | |
if(i < MAXN) { | |
A[i][j] = max(A[2 * i][j], A[2 * i + 1][j]); | |
} else if(j < MAXN) { | |
A[i][j] = max(A[i][2 * j], A[i][2 * j + 1]); | |
} | |
} | |
} | |
scanf("%d%d%d", &RA, &RB, &RM); | |
long long sum = 0; | |
for(int i = 0; i < Q; i++) { | |
int s = 1 + next_rand() % N; | |
int r = 1 + next_rand() % (N - s + 1); | |
int c = 1 + next_rand() % (N - s + 1); | |
r--; c--; | |
sum += get_r(1, 0, MAXN, r, r + s, c, c + s); | |
} | |
printf("%lld\n", sum); | |
return 0; | |
} |
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