We can make this file beautiful and searchable if this error is corrected: It looks like row 2 should actually have 3 columns, instead of 2 in line 1.
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Alabama 2,265,090 Republican | |
Alaska 338,177 Republican | |
Arizona 3,390,161 Republican | |
Arkansas 1,182,676 Republican | |
California 15,865,475 Democratic | |
Colorado 3,192,745 Democratic | |
Connecticut 1,759,010 Democratic | |
Delaware 512,912 Democratic | |
District of Columbia 325,869 Democratic | |
Florida 10,893,752 Republican |
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Place | Economics | HumanCapital | QOL | Environment | Governance | |
---|---|---|---|---|---|---|
New York United States | 1 | 4 | 278 | 353 | 184 | |
London United Kingdom | 7 | 1 | 292 | 197 | 72 | |
San Jose United States | 3 | 28 | 38 | 53 | 184 | |
Tokyo Japan | 10 | 2 | 218 | 277 | 26 | |
Paris France | 9 | 6 | 65 | 409 | 161 | |
Seattle United States | 4 | 40 | 56 | 40 | 184 | |
Los Angeles United States | 2 | 19 | 280 | 79 | 184 | |
San Francisco United States | 5 | 34 | 101 | 62 | 184 | |
Melbourne Australia | 16 | 11 | 185 | 30 | 18 |
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# Find x such that x+1, 2x+3,3x+5 and 4x+7 are prime. | |
library(DescTools) | |
# This works | |
subset(expand.grid(x=1:1000),IsPrime(x+1) & IsPrime(2*x+3) & IsPrime(3*x+5) & IsPrime(4*x+7)) | |
# Alternate solution | |
which(mapply(function(x) IsPrime(x+1) & IsPrime(2*x+3) & IsPrime(3*x+5) & IsPrime(4*x+7), 1:1000)) |
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dim(subset(expand.grid(a=0:80,b=seq(2,80,2),c=c(0,2,5)), a+b+c == 80)) |
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x<-0:9 | |
n<-4 | |
N<-100000 | |
atleasttwomatch<- 0 | |
allfourmatch<-0 | |
for(i in 1:N) { | |
a<-sample(x,n) | |
b<-sample(x,n) | |
s<-length(a[is.element(a, b)]) | |
if (s > 1) { |
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x<-seq(1,20) | |
n<-100000 | |
mx<-c() | |
for (i in 1:n) { | |
mx<-c(mx,max(sample(x,10,replace=F))) | |
} | |
summary(mx) | |
Min. 1st Qu. Median Mean 3rd Qu. Max. |
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> x<-runif(100,0,2) | |
> y<-1+x+x^2+x^3 | |
> summary(lm(y~x)) | |
Call: | |
lm(formula = y ~ x) | |
Residuals: | |
Min 1Q Median 3Q Max | |
-1.334 -1.018 -0.213 0.677 2.742 |
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rm(list=ls()) | |
library(rstan) | |
rstan_options(auto_write = FALSE) | |
options(mc.cores = parallel::detectCores()) | |
N=1000 | |
data = list(N=N,x1<-rnorm(N,5,2),x2<-rnorm(N,7,2),x3<-rnorm(N,9,2),y<-x1+x2+x3) | |
fit <- suppressMessages(stan(file = '~/Desktop/695/test.stan', data = data, iter=11000, warmup=1000, chains=2, seed=483892929, refresh=11000)) | |
print(fit) | |
plot(fit) |
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rm(list =ls()) | |
dev.off() | |
for(j in 1:4) { | |
n=1000 | |
x=numeric(n) | |
y=numeric(n) | |
x[1] = rnorm(1,0,0.2) | |
y[1] = rnorm(1,0,0.2) | |
a=0.51 |
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# Goal: Find unknown scalar w to minimize L(w) | |
# L(w) = sum((y[i] - w*x[i])^2) | |
# (x[i], y[i]), i=1..n dataset for linear regression | |
# | |
# Repeat Iterative Procedure below until convergence: | |
# w[i+1] = w[i] - alpha * gradient(L(w), w=w[i]) | |
# | |
set.seed(12345) | |
x=seq(-5,5,0.5) | |
y = 2*x + rnorm(length(x),0,1) |
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