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@kriskowal
Forked from ryanwitt/huffman.py
Created July 24, 2012 16:32
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silly huffman coding example
__all__ = (
'build',
'endode',
'decode',
)
phrase = 'A man a plan a canal Panama'.lower()
def build(phrase):
"""
>>> build(phrase)
[('a', 10), (' ', 6), ('n', 4), ('p', 2), ('l', 2), ('m', 2), ('c', 1)]
"""
d = {}
for c in phrase:
d[c] = d.get(c, 0) + 1
return list(reversed(sorted(d.items(), key = lambda (key, value): key)))
def encode(phrase, tree=None):
"""
>>> ''.join(encode(phrase))
'01011111001101001011101111001101001011111100110011110101110011001111100'
"""
if tree is None:
tree = build(phrase)
for c in phrase:
for character, count in tree:
if character == c:
yield '0'
break
else:
yield '1'
def decode(phrase, tree):
"""
>>> ''.join(decode('01011111001101001011101111001101001011111100110011110101110011001111100', build(phrase)))
'a man a plan a canal panama'
"""
cur = iter(tree)
for c in phrase:
if c == '1':
cur.next()
elif c == '0':
yield cur.next()[0]
cur = iter(tree)
#print ''.join(bin(ord(c)).replace('b','') for c in phrase)
#print ''.join(encode(phrase))
def tree2dot(tree):
print 'digraph g {'
last = 'root'
i = 0
for c,freq in tree:
print last, '-> ', c.replace(' ','space'), ' [label=0];'
new = bin(i).replace('b','')
print last, '->', new, '[label=1];'
last = new
i += 1
print '}'
print
tree2dot(build(phrase))
@kriskowal
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Author

Nice.

A couple small opportunities:

list(reversed(sorted(d.items(), key = lambda (key, value): key)))

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