Created
April 28, 2017 18:54
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Simple implementation of a queue using linked list in C
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#include <stdio.h> | |
#include <stdlib.h> | |
typedef struct node { | |
int val; | |
struct node *next; | |
} node_t; | |
void enqueue(node_t **head, int val) { | |
node_t *new_node = malloc(sizeof(node_t)); | |
if (!new_node) return; | |
new_node->val = val; | |
new_node->next = *head; | |
*head = new_node; | |
} | |
int dequeue(node_t **head) { | |
node_t *current, *prev = NULL; | |
int retval = -1; | |
if (*head == NULL) return -1; | |
current = *head; | |
while (current->next != NULL) { | |
prev = current; | |
current = current->next; | |
} | |
retval = current->val; | |
free(current); | |
if (prev) | |
prev->next = NULL; | |
else | |
*head = NULL; | |
return retval; | |
} | |
void print_list(node_t *head) { | |
node_t *current = head; | |
while (current != NULL) { | |
printf("%d\n", current->val); | |
current = current->next; | |
} | |
} | |
int main() { | |
node_t *head = NULL; | |
int ret; | |
enqueue(&head, 11); | |
enqueue(&head, 22); | |
enqueue(&head, 33); | |
enqueue(&head, 44); | |
print_list(head); | |
while ((ret=dequeue(&head)) > 0) { | |
printf("dequeued %d\n", ret); | |
} | |
printf("done. head=%p\n", head); | |
return 0; | |
} |
#include <stdio.h>
#include <stdlib.h>
typedef struct elem {
int Data;
struct elem *next;
} TElem;
TElem *createElem(int i) {
TElem *newElem = malloc(sizeof(TElem));
newElem -> Data = i;
newElem -> next = NULL;
return newElem;
}
void addToQ(TElem *newElem, TElem **Head, TElem **Tail) {
newElem -> next = *Head;
*Head = newElem;
if (newElem -> next == NULL) {
*Tail = newElem;
}
}
void getQ(TElem *Head) {
TElem *temp = Head;
while (temp != NULL) {
printf("element %d\n", temp -> Data);
temp = temp -> next;
}
}
int main() {
TElem *Head = NULL;
TElem *Tail = NULL;
for (int i = 0; i < 10; i++) {
addToQ(createElem(i), &Head, &Tail);
}
getQ(Head);
}
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You can change it to hold pointers instead of integers