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Emoji Checking for Swift 5.0 and up
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import Foundation | |
extension Character { | |
/// A simple emoji is one scalar and presented to the user as an Emoji | |
var isSimpleEmoji: Bool { | |
return unicodeScalars.count == 1 && unicodeScalars.first?.properties.isEmojiPresentation ?? false | |
} | |
/// Checks if the scalars will be merged into and emoji | |
var isCombinedIntoEmoji: Bool { | |
return unicodeScalars.count > 1 && | |
unicodeScalars.contains { $0.properties.isJoinControl || $0.properties.isVariationSelector } | |
} | |
var isEmoji: Bool { | |
return isSimpleEmoji || isCombinedIntoEmoji | |
} | |
} | |
extension String { | |
var isSingleEmoji: Bool { | |
return count == 1 && containsEmoji | |
} | |
var containsEmoji: Bool { | |
return contains { $0.isEmoji } | |
} | |
var containsOnlyEmoji: Bool { | |
return !isEmpty && !contains { !$0.isEmoji } | |
} | |
var emojiString: String { | |
return emojis.map { String($0) }.reduce("", +) | |
} | |
var emojis: [Character] { | |
filter { $0.isEmoji } | |
} | |
var emojiScalars: [UnicodeScalar] { | |
return filter{ $0.isEmoji }.flatMap { $0.unicodeScalars } | |
} | |
} | |
"A̛͚̖".containsEmoji // false | |
"3".containsEmoji // false | |
"3️⃣".isSingleEmoji // true | |
"👌🏿".isSingleEmoji // true | |
"🙎🏼♂️".isSingleEmoji // true | |
"👨👩👧👧".isSingleEmoji // true | |
"👨👩👧👧".containsOnlyEmoji // true | |
"Hello 👨👩👧👧".containsOnlyEmoji // false | |
"Hello 👨👩👧👧".containsEmoji // true | |
"👫 Héllo 👨👩👧👧".emojiString // "👫👨👩👧👧" | |
"👨👩👧👧".count // 1 | |
"👫 Héllœ 👨👩👧👧".emojiScalars // [128107, 128104, 8205, 128105, 8205, 128103, 8205, 128103] | |
"👫 Héllœ 👨👩👧👧".emojis // ["👫", "👨👩👧👧"] | |
"👫 Héllœ 👨👩👧👧".emojis.count // 2 | |
"👫👨👩👧👧👨👨👦".isSingleEmoji // false | |
"👫👨👩👧👧👨👨👦".containsOnlyEmoji // true |
In line 12 make sure to add isEmojiModifier
to the OR, otherwise skin tone emojis won't be recognized
It doesn't recognize these characters as emojis:
‼, ⁉, ©, ®, ↔, ↕, ↖, ↗, ↘, ↙, ↩, ↪, ⌚, ⌛, ⌨, ℹ, ™
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@lk251
I found flags's
isEmojiPresentation
is true, but it's scalar is not only one, it's plural(mostly 2, someone is 7(🏴,🏴,🏴)so flags can't pass
isCombinedIntoEmoji
neitherisSimpleEmoji
...I just want to block emoji input, so i adjust
isSimpleEmoji
with only checkingisEmojiPresentation
, not it's count == 1thanks for sharing @krummler 🙏🙏 it's really help to me☺️