PhotoSwipe: init from DOM using jQuery

jquery.photoswipe.js

(function( $ ) {
    $.fn.photoswipe = function(options){
        var galleries = [],
            _options = options;
        
        var init = function($this){
            galleries = [];
            $this.each(function(i, gallery){
                galleries.push({
                    id: i,
                    items: []
                });

                $(gallery).find('a').each(function(k, link) {
                    var $link = $(link),
                        size = $link.data('size').split('x');
                    if (size.length != 2){
                        throw SyntaxError("Missing data-size attribute.");
                    }
                    $link.data('gallery-id',i+1);
                    $link.data('photo-id', k);

                    var item = {
                        src: link.href,
                        msrc: link.children[0].getAttribute('src'),
                        w: parseInt(size[0],10),
                        h: parseInt(size[1],10),
                        title: $link.data('title'),
                        el: link
                    }
                        
                    galleries[i].items.push(item);
                    
                });

                $(gallery).on('click', 'a', function(e){
                    e.preventDefault();
                    var gid = $(this).data('gallery-id'),
                        pid = $(this).data('photo-id');
                    openGallery(gid,pid);
                });
            });
        }
        
        var parseHash = function() {
            var hash = window.location.hash.substring(1),
            params = {};

            if(hash.length < 5) {
                return params;
            }

            var vars = hash.split('&');
            for (var i = 0; i < vars.length; i++) {
                if(!vars[i]) {
                    continue;
                }
                var pair = vars[i].split('=');  
                if(pair.length < 2) {
                    continue;
                }           
                params[pair[0]] = pair[1];
            }

            if(params.gid) {
                params.gid = parseInt(params.gid, 10);
            }

            if(!params.hasOwnProperty('pid')) {
                return params;
            }
            params.pid = parseInt(params.pid, 10);
            return params;
        };
        
        var openGallery = function(gid,pid){
            var pswpElement = document.querySelectorAll('.pswp')[0],
                items = galleries[gid-1].items,
                options = {
                    index: pid,
                    galleryUID: gid,
                    getThumbBoundsFn: function(index) {
                        var thumbnail = items[index].el.children[0],
                            pageYScroll = window.pageYOffset || document.documentElement.scrollTop,
                            rect = thumbnail.getBoundingClientRect(); 

                        return {x:rect.left, y:rect.top + pageYScroll, w:rect.width};
                    }
                };
            $.extend(options,_options);
            var gallery = new PhotoSwipe( pswpElement, PhotoSwipeUI_Default, items, options);
            gallery.init();
        }
        
        // initialize
        init(this);
        
        // Parse URL and open gallery if it contains #&pid=3&gid=1
        var hashData = parseHash();
        if(hashData.pid > 0 && hashData.gid > 0) {
            openGallery(hashData.gid,hashData.pid);
        }
        
        return this;
    };
}( jQuery ));

Hello, just sorry for my bad English. The problem is this, there is a picture, when you hover over it, there are icons, how to make that PhotoSwipe launched by clicking on the icon? Thanks in advance

hi @o-l-e, its possible if i just use 1 image size but i want to be responsive image? like img-responsive class in bootstrap .

Hi there,

The above creates separate galleries for "div.my-simple-gallery".
How can I modify the code so that there is only 1 gallery for all child elements?

eg.

<div class="my-simple-gallery">
<img 1>
</div>
<div class="my-simple-gallery">
<img 2>
</div>

etc..

Apologies as I'm not well versed in JS. Any help would be greatly appreciated thank you!

@kshnurov this is awesome, just what I need. Notice one weird thing, when you Parse URL and open gallery in new window, if it's pid1 of each gallery it updates to pid2 and shows the second image.

Looking at the fix just now but thought I'd point it out.... thanks for the code!

In the openGallery() function, options.index should be pid-1 instead of just pid, guess index starts from zero.. -> this fixes deep linking to the first image.