Skip to content

Instantly share code, notes, and snippets.

@ktcy
Created September 18, 2015 11:33
Show Gist options
  • Save ktcy/b6c33172a4d933d0bfdc to your computer and use it in GitHub Desktop.
Save ktcy/b6c33172a4d933d0bfdc to your computer and use it in GitHub Desktop.
'use strict';
/*
* Copyright (C) 2008 Apple Inc. All Rights Reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
*
* THIS SOFTWARE IS PROVIDED BY APPLE INC. ``AS IS'' AND ANY
* EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR
* PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL APPLE INC. OR
* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
* EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
* PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR
* PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY
* OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
* OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
export default class UnitBezier {
constructor(x1, y1, x2, y2) {
// Calculate the polynomial coefficients, implicit first and last control points are (0,0) and (1,1).
this.cx = 3 * x1;
this.bx = 3 * (x2 - x1) - this.cx;
this.ax = 1 - this.cx - this.bx;
this.cy = 3 * y1;
this.by = 3 * (y2 - y1) - this.cy;
this.ay = 1 - this.cy - this.by;
// End-point gradients are used to calculate timing function results
// outside the range [0, 1].
//
// There are three possibilities for the gradient at each end:
// (1) the closest control point is not horizontally coincident with regard to
// (0, 0) or (1, 1). In this case the line between the end point and
// the control point is tangent to the bezier at the end point.
// (2) the closest control point is coincident with the end point. In
// this case the line between the end point and the far control
// point is tangent to the bezier at the end point.
// (3) the closest control point is horizontally coincident with the end
// point, but vertically distinct. In this case the gradient at the
// end point is Infinite. However, this causes issues when
// interpolating. As a result, we break down to a simple case of
// 0 gradient under these conditions.
if (x1 > 0) {
this.startGradient = y1 / x1;
} else if (!y1 && x2 > 0) {
this.startGradient = y2 / x2;
} else {
this.startGradient = 0;
}
if (x2 < 1) {
this.endGradient = (y2 - 1) / (x2 - 1);
} else if (p2x === 1 && x1 < 1) {
this.endGradient = (y1 - 1) / (x1 - 1);
} else {
this.endGradient = 0;
}
}
sampleCurveX(t) {
// `ax t^3 + bx t^2 + cx t' expanded using Horner's rule.
return ((this.ax * t + this.bx) * t + this.cx) * t;
}
sampleCurveY(t) {
return ((this.ay * t + this.by) * t + this.cy) * t;
}
sampleCurveDerivativeX(t) {
return (3 * this.ax * t + 2 * this.bx) * t + this.cx;
}
// Given an x value, find a parametric value it came from.
solveCurveX(x, epsilon) {
let t0, t1, t2, x2, d2, i;
// First try a few iterations of Newton's method -- normally very fast.
for (t2 = x, i = 0; i < 8; i++) {
x2 = this.sampleCurveX(t2) - x;
if (Math.abs(x2) < epsilon) {
return t2;
}
d2 = this.sampleCurveDerivativeX(t2);
if (Math.abs(d2) < 0.000001) {
break;
}
t2 = t2 - x2 / d2;
}
// Fall back to the bisection method for reliability.
t0 = 0;
t1 = 1;
t2 = x;
while (t0 < t1) {
x2 = this.sampleCurveX(t2);
if (Math.abs(x2 - x) < epsilon) {
return t2;
}
if (x > x2) {
t0 = t2;
} else {
t1 = t2;
}
t2 = (t1 - t0) * 0.5 + t0;
}
// Failure.
return t2;
}
// Evaluates y at the given x. The epsilon parameter provides a hint as to the required
// accuracy and is not guaranteed.
solve(x, epsilon) {
if (x <= 0) {
return this.startGradient * x;
}
if (x >= 1) {
return 1 + this.endGradient * (x - 1);
}
return this.sampleCurveY(this.solveCurveX(x, epsilon));
}
}
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment