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September 24, 2020 05:52
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Gas Station
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""" | |
There are N gas stations along a circular route, where the amount of gas at station i is gas[i]. | |
You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next | |
station (i+1). You begin the journey with an empty tank at one of the gas stations. | |
Return the starting gas station's index if you can travel around the circuit once in the clockwise direction, | |
otherwise return -1. | |
Note: | |
If there exists a solution, it is guaranteed to be unique. | |
Both input arrays are non-empty and have the same length. | |
Each element in the input arrays is a non-negative integer. | |
Example 1: | |
Input: | |
gas = [1,2,3,4,5] | |
cost = [3,4,5,1,2] | |
Output: 3 | |
Explanation: | |
Start at station 3 (index 3) and fill up with 4 unit of gas. Your tank = 0 + 4 = 4 | |
Travel to station 4. Your tank = 4 - 1 + 5 = 8 | |
Travel to station 0. Your tank = 8 - 2 + 1 = 7 | |
Travel to station 1. Your tank = 7 - 3 + 2 = 6 | |
Travel to station 2. Your tank = 6 - 4 + 3 = 5 | |
Travel to station 3. The cost is 5. Your gas is just enough to travel back to station 3. | |
Therefore, return 3 as the starting index. | |
Example 2: | |
Input: | |
gas = [2,3,4] | |
cost = [3,4,3] | |
Output: -1 | |
Explanation: | |
You can't start at station 0 or 1, as there is not enough gas to travel to the next station. | |
Let's start at station 2 and fill up with 4 unit of gas. Your tank = 0 + 4 = 4 | |
Travel to station 0. Your tank = 4 - 3 + 2 = 3 | |
Travel to station 1. Your tank = 3 - 3 + 3 = 3 | |
You cannot travel back to station 2, as it requires 4 unit of gas but you only have 3. | |
Therefore, you can't travel around the circuit once no matter where you start. | |
Time, Space = O(n), O(1) | |
""" | |
from typing import List | |
class Solution: | |
def canCompleteCircuit(self, gas: List[int], cost: List[int]) -> int: | |
n = len(gas) | |
curr_tank = total_tank = 0 | |
starting_station = 0 | |
for i in range(n): | |
total_tank += gas[i] - cost[i] | |
curr_tank += gas[i] - cost[i] | |
if curr_tank < 0: # gas exhausted | |
starting_station = i + 1 # start journey from next station | |
curr_tank = 0 | |
return starting_station if total_tank >= 0 else -1 |
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