Created
October 20, 2012 03:29
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implementing DES-X (mode CBC) using PyCrypto
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| ''' | |
| This code implements DES-X mode CBC efficiently using PyCrypto | |
| ''' | |
| from Crypto.Cipher import DES | |
| def des_x(plaintext, key, iv='\0'*8): | |
| 'key must be 24 bytes, plaintext must be multiple of 8 bytes' | |
| pre_whiten = XOR.new(key[ 8:16]).encrypt #XOR -- encrypt/decrypt are the same | |
| post_whiten = XOR.new(key[16:24]).encrypt | |
| encrypt = DES.new(key[:8], mode=DES.MODE_ECB).encrypt | |
| out = [] | |
| prev_xor = XOR.new(iv).encrypt | |
| for i in xrange(len(key)/8): | |
| cur_plain = plaintext[i*8:i*8+8] | |
| cur_cipher = post_whiten(encrypt(pre_whiten(prev_xor(cur_plain)))) | |
| out.append(cur_cipher) | |
| prev_xor = XOR.new(cur_cipher).encrypt | |
| return b"".join(out) | |
| def un_des_x(ciphertext, key, iv='\0'*8): | |
| 'key must be 24 bytes, plaintext must be multiple of 8 bytes' | |
| pre_whiten = XOR.new(key[ 8:16]).decrypt | |
| post_whiten = XOR.new(key[16:24]).decrypt | |
| decrypt = DES.new(key[:8], mode=DES.MODE_ECB).decrypt | |
| out = [] | |
| prev_xor = XOR.new(iv).decrypt | |
| for i in xrange(len(ciphertext)/8): | |
| cur_cipher = ciphertext[i*8:i*8+8] | |
| cur_plain = prev_xor(pre_whiten(decrypt(post_whiten(cur_cipher)))) | |
| out.append(cur_plain) | |
| prev_xor = XOR.new(cur_cipher).decrypt | |
| return b"".join(out) |
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