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April 21, 2016 01:31
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Odd = Red Ball, Even = Blue Ball
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# The adding logic seems to dictate the result. So if you start with 1 ball each (differnt colors / odd), | |
# you end up with red. | |
blue_balls = Array.new(17, 'blue') | |
red_balls = Array.new(17, 'red') | |
balls = red_balls + blue_balls | |
balls.shuffle! | |
puts "Starting Ball List: #{balls}" | |
while balls.count > 1 | |
take_2 = balls.shift(2) | |
puts "grabbing 2 balls: #{take_2}" | |
if take_2.uniq.count == 1 # balls are the same color | |
balls.push('blue') # add a blue ball back | |
puts "+1 blue" | |
elsif take_2.uniq.count == 2 # balls are differnt colors | |
balls.push('red') # add a red ball back | |
puts "+1 red" | |
end | |
end | |
puts "Last Ball Remaining: #{balls}" |
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