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December 9, 2012 05:58
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Project Euler #24 in Go - Answer: [2 7 8 3 9 1 5 4 6 0]
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package main | |
import ( | |
"fmt" | |
) | |
const Max = 10 | |
const Index = 1000000 | |
func main() { | |
numbers := make([]byte, 0, Max) | |
for i := 0; i < Max; i++ { | |
numbers = append(numbers, byte(i)) | |
} | |
result = make(chan [Max]byte, 1) | |
index = 0 | |
perm(numbers, 0, len(numbers)) | |
if len(result) > 0 { | |
fmt.Println(<-result) | |
} | |
} | |
var index int | |
var result chan [Max]byte | |
func perm(numbers []byte, lo, hi int) { | |
if index > Index { | |
return | |
} | |
if hi-lo < 2 { | |
if index++; index == Index { | |
var p [Max]byte | |
copy(p[:], numbers) | |
result <- p | |
} | |
return | |
} | |
for i := 1; i < hi-lo+1; i++ { | |
rotateR(numbers, lo, lo+i) | |
perm(numbers, lo+1, hi) | |
rotateL(numbers, lo, lo+i) | |
} | |
} | |
func rotateL(numbers []byte, lo, hi int) { | |
for i := lo + 1; i < hi; i++ { | |
numbers[i-1], numbers[i] = numbers[i], numbers[i-1] | |
} | |
} | |
func rotateR(numbers []byte, lo, hi int) { | |
for i := hi - 1; i > lo; i-- { | |
numbers[i-1], numbers[i] = numbers[i], numbers[i-1] | |
} | |
} |
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package main | |
import ( | |
"fmt" | |
) | |
const Max = 10 | |
const Index = 1000000 | |
func main() { | |
digits := make([]byte, 0, Max) | |
for i := byte(0); i < Max; i++ { | |
digits = append(digits, i) | |
} | |
rem := Index - 1 | |
res := make([]byte, 0, Max) | |
for i := Max - 1; i >= 0; i-- { | |
f := fact(i) | |
quo := rem / f | |
rem = rem % f | |
res = append(res, digits[quo]) | |
digits = append(digits[:quo], digits[quo+1:]...) | |
} | |
fmt.Println(res) | |
} | |
func fact(n int) int { | |
if n < 2 { | |
return 1 | |
} | |
return n * fact(n-1) | |
} |
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