kzhk75/p6_NCID_BA67904578.md

Last active May 1, 2020 13:53

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$ m \left(\frac{d^2 }{d t^2} + \omega^2 \right)x = 0 $

$ m \left(\frac{d^2 x }{d t^2} + \omega^2 x \right) = 0 $

$ m \left(\frac{d \dot{x} }{d t} + \omega^2 x \right) = 0 $

$ m \left(\frac{d \dot{x} }{d t} + \omega^2 x \right) \cdot \dot{x} = 0 \cdot \dot{x} $

$ m \left[ \frac{d}{dt} \left( \frac{1}{2} \dot{x}^2 \right) + \frac{d}{dt} \left( \omega^2 \frac{1}{2} x^2 \right) \right] =0 $