Created
January 31, 2014 13:35
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Because my other 5 line Erlang solution was too long.
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| -module(problem_2). | |
| -export([s/0]). | |
| -define(L, 4000000). | |
| s() -> s(1, 2, 0). | |
| s(P, N, S) when P >= ?L; N >= ?L -> S; | |
| s(P, N, S) -> S1 = case N rem 2 of 0 -> N + S; _ -> S end, s(N, P + N, S1). |
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