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date use
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date +%s 可以得到UNIX的时间戳; | |
用shell将时间字符串与时间戳互转: | |
date -d "2010-10-18 00:00:00" +%s 输出形如:1287331200 | |
而时间戳转换为字符串可以这样做: | |
date -d @1287331200 "+%Y-%m-%d" 输出形如:2010-10-18 | |
如果需要得到指定日期的前后几天,可以: | |
1、seconds=`date -d "2010-10-18 00:00:00" +%s` #得到时间戳 | |
2、seconds_new=`expr $seconds + 86400` #加上一天的秒数86400 | |
3、date_new=`date -d @$seconds_new "+%Y-%m-%d"` #获得指定日前加上一天的日前 |
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